Assuming the cost of an arbitrary house as $500,000, the density of silver as 10,490 kg/m³ and if we retain the thickness-to-diameter ratio of a $1 dollar coin (around 0.065), we need 680.27 kg ($735/kg) of silver, which, distributed to 10 silver coins, would result in each silver coin having a diameter of 50.27 cm, or 19.79 inch.
Assuming the cost of an arbitrary house as $500,000, the density of silver as 10,490 kg/m³ and if we retain the thickness-to-diameter ratio of a $1 dollar coin (around 0.065), we need 680.27 kg ($735/kg) of silver, which, distributed to 10 silver coins, would result in each silver coin having a diameter of 50.27 cm, or 19.79 inch.