I’m not sure what you mean by in there but yes, the heat would be transferred to the environment.
E=m(c^2) describes how much energy is contained in matter. It’s useful for nuclear reactions, but your body isn’t a nuclear reactor and you aren’t consuming substantial quantities of radioactive isotopes, like uranium ore, that will decay on their own so it isn’t relevant here.
Something has to go in there, if not losing energy to radiant heat transfer, then how e=m(c^2)?
I’m not sure what you mean by in there but yes, the heat would be transferred to the environment.
E=m(c^2) describes how much energy is contained in matter. It’s useful for nuclear reactions, but your body isn’t a nuclear reactor and you aren’t consuming substantial quantities of radioactive isotopes, like uranium ore, that will decay on their own so it isn’t relevant here.
Still energy is being radiated. A mass loss has to occur for that